Optimal. Leaf size=253 \[ -\frac {(e x)^{m+1} \left (a+b x^2\right )^p \left (\frac {b x^2}{a}+1\right )^{-p} \, _2F_1\left (\frac {m+1}{2},-p;\frac {m+3}{2};-\frac {b x^2}{a}\right ) (A b (m+2 p+3) (a d (m+1)-b c (m+2 p+5))-a (m+1) (a B d (m+3)-b (2 A d+B c (m+2 p+5))))}{b^2 e (m+1) (m+2 p+3) (m+2 p+5)}-\frac {(e x)^{m+1} \left (a+b x^2\right )^{p+1} (a B d (m+3)-b (2 A d+B c (m+2 p+5)))}{b^2 e (m+2 p+3) (m+2 p+5)}+\frac {d \left (A+B x^2\right ) (e x)^{m+1} \left (a+b x^2\right )^{p+1}}{b e (m+2 p+5)} \]
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Rubi [A] time = 0.23, antiderivative size = 238, normalized size of antiderivative = 0.94, number of steps used = 4, number of rules used = 4, integrand size = 29, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.138, Rules used = {581, 459, 365, 364} \[ \frac {(e x)^{m+1} \left (a+b x^2\right )^{p+1} (-a B d (m+3)+2 A b d+b B c (m+2 p+5))}{b^2 e (m+2 p+3) (m+2 p+5)}-\frac {(e x)^{m+1} \left (a+b x^2\right )^p \left (\frac {b x^2}{a}+1\right )^{-p} \, _2F_1\left (\frac {m+1}{2},-p;\frac {m+3}{2};-\frac {b x^2}{a}\right ) \left (\frac {a (-a B d (m+3)+2 A b d+b B c (m+2 p+5))}{b (m+2 p+3)}+a A d-\frac {A b c (m+2 p+5)}{m+1}\right )}{b e (m+2 p+5)}+\frac {d \left (A+B x^2\right ) (e x)^{m+1} \left (a+b x^2\right )^{p+1}}{b e (m+2 p+5)} \]
Antiderivative was successfully verified.
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Rule 364
Rule 365
Rule 459
Rule 581
Rubi steps
\begin {align*} \int (e x)^m \left (a+b x^2\right )^p \left (A+B x^2\right ) \left (c+d x^2\right ) \, dx &=\frac {d (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (A+B x^2\right )}{b e (5+m+2 p)}+\frac {\int (e x)^m \left (a+b x^2\right )^p \left (-A (a d (1+m)-b c (5+m+2 p))+(2 A b d-a B d (3+m)+b B c (5+m+2 p)) x^2\right ) \, dx}{b (5+m+2 p)}\\ &=\frac {(2 A b d-a B d (3+m)+b B c (5+m+2 p)) (e x)^{1+m} \left (a+b x^2\right )^{1+p}}{b^2 e (3+m+2 p) (5+m+2 p)}+\frac {d (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (A+B x^2\right )}{b e (5+m+2 p)}-\frac {\left (A (a d (1+m)-b c (5+m+2 p))+\frac {a (1+m) (2 A b d-a B d (3+m)+b B c (5+m+2 p))}{b (3+m+2 p)}\right ) \int (e x)^m \left (a+b x^2\right )^p \, dx}{b (5+m+2 p)}\\ &=\frac {(2 A b d-a B d (3+m)+b B c (5+m+2 p)) (e x)^{1+m} \left (a+b x^2\right )^{1+p}}{b^2 e (3+m+2 p) (5+m+2 p)}+\frac {d (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (A+B x^2\right )}{b e (5+m+2 p)}-\frac {\left (\left (A (a d (1+m)-b c (5+m+2 p))+\frac {a (1+m) (2 A b d-a B d (3+m)+b B c (5+m+2 p))}{b (3+m+2 p)}\right ) \left (a+b x^2\right )^p \left (1+\frac {b x^2}{a}\right )^{-p}\right ) \int (e x)^m \left (1+\frac {b x^2}{a}\right )^p \, dx}{b (5+m+2 p)}\\ &=\frac {(2 A b d-a B d (3+m)+b B c (5+m+2 p)) (e x)^{1+m} \left (a+b x^2\right )^{1+p}}{b^2 e (3+m+2 p) (5+m+2 p)}+\frac {d (e x)^{1+m} \left (a+b x^2\right )^{1+p} \left (A+B x^2\right )}{b e (5+m+2 p)}-\frac {\left (A (a d (1+m)-b c (5+m+2 p))+\frac {a (1+m) (2 A b d-a B d (3+m)+b B c (5+m+2 p))}{b (3+m+2 p)}\right ) (e x)^{1+m} \left (a+b x^2\right )^p \left (1+\frac {b x^2}{a}\right )^{-p} \, _2F_1\left (\frac {1+m}{2},-p;\frac {3+m}{2};-\frac {b x^2}{a}\right )}{b e (1+m) (5+m+2 p)}\\ \end {align*}
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Mathematica [A] time = 0.13, size = 147, normalized size = 0.58 \[ x (e x)^m \left (a+b x^2\right )^p \left (\frac {b x^2}{a}+1\right )^{-p} \left (\frac {x^2 (A d+B c) \, _2F_1\left (\frac {m+3}{2},-p;\frac {m+5}{2};-\frac {b x^2}{a}\right )}{m+3}+\frac {A c \, _2F_1\left (\frac {m+1}{2},-p;\frac {m+3}{2};-\frac {b x^2}{a}\right )}{m+1}+\frac {B d x^4 \, _2F_1\left (\frac {m+5}{2},-p;\frac {m+7}{2};-\frac {b x^2}{a}\right )}{m+5}\right ) \]
Antiderivative was successfully verified.
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fricas [F] time = 0.95, size = 0, normalized size = 0.00 \[ {\rm integral}\left ({\left (B d x^{4} + {\left (B c + A d\right )} x^{2} + A c\right )} {\left (b x^{2} + a\right )}^{p} \left (e x\right )^{m}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (B x^{2} + A\right )} {\left (d x^{2} + c\right )} {\left (b x^{2} + a\right )}^{p} \left (e x\right )^{m}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.07, size = 0, normalized size = 0.00 \[ \int \left (B \,x^{2}+A \right ) \left (d \,x^{2}+c \right ) \left (e x \right )^{m} \left (b \,x^{2}+a \right )^{p}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (B x^{2} + A\right )} {\left (d x^{2} + c\right )} {\left (b x^{2} + a\right )}^{p} \left (e x\right )^{m}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \left (B\,x^2+A\right )\,{\left (e\,x\right )}^m\,{\left (b\,x^2+a\right )}^p\,\left (d\,x^2+c\right ) \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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